Solve the equation sin 30° * cos 30° — tg 60° to decide
11 january 2017, 00:54
Solve the equation sin 30° cos 30° tg 60° to solve
12 sqrt32 sqrt3=-3корня 3
cos30=corn h 32
12 corn z 3 2 - z 3 corn =
In isosceles trapezoid ABCD, AD II VS A = 30° height VC = 1 cm, VS= 2 cm, Find the area of the triangle KMD if M is the midpoint of the segment
ASD - line MT perpendicular to AD. S=KDMT MT - middle line DVK
MT=VC =1= CD=CO+OD FROM normal to HELL .AVK=SOD
=AV-VC=4-1=3. KD=2+3. S=2+3=2+34
The answer is 2+34cm
The number of books on the first shelf 20% more than the number on Toranaga shifted from the first 3 books in the second the number was equally how many books
x number of books on the second shelf
12x on the first shelf
x=30 books on the second shelf
Suppose that x is the number of books on the second shelf then 12x is the number of books on the first shelf
according to these data we set up and solve the equation
x=30 K. II was on the shelf.
12x=1230=36 K. I was on the shelf.
The answer to the second shelf was originally 30 books.
find the sum of an infinite progression 126
b1 = 12 q = 12
S = b11, q= 121-12=1205=24
S=b1-b g=12 g=612=
Ответ6 24 .
Find the surface area of a rectangular parallelepipedon which 6смширина2сма height 3 canidite the sum of the lengths of all its
The sum of the lengths of all edges = 64+34+24=46+3+2=611=44 cm
S=263+262+232=36+24+12=72 cm sq surface area of a rectangular parallelepiped
L=46+42+43=24+8+12= 44 cm the sum of the lengths of all its rber
prelomi task back proportionalist with almost nine months
For the construction of the stadium 5 bulldozers cleared the area for 210 minutes time 7 bulldozers cleared the site
5 cars 210 min.
7 machines min.
The relationship between number of machines and the operating time is inversely proportional
we make a proportion
7 5 = 210 x
x=150 minutes, or 25 hours 7 bulldozers clear the site
Answer in 25 hours 7 bulldozers clear the site
the store brought in 14 tons of cabbage, 30% sold. how much cabbage is left
The tour went 56 storeclusterskinfile 27 mensagem Torocheshnikova of tracelessness-14 more than parseclassnames How much
Response 43 29 first-graders, a third grader.
1кл to 27m than 2
3 KL 14 b than 1 C
56-27=29 first graders
29+14= 43 tracelessness
The perimeter of an isosceles triangle is equal to 105 MCA lateral side refers to the base 73 by this Way
Let one of the accounts x stogda the base is equal to 3 SMA side equal to 7x see Make the equation-3x+7x+7x=10517х=105х=6
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